Stem-and-leaf plots and grouped means
Preserve exact values where possible and label estimates that use class midpoints.
More
Offline pages
Saved on this device only. Connect at least once every 30 days to confirm Premium. Sign-out or a change of account removes saved copies.
Find this activity in your course
On this page
You stopped at:
ContinueRevision Mode is on. Questions and activities are hidden.
A stem-and-leaf plot keeps each observation
For scores 12, 14, 14, 18, 21 and 25, an ordered plot is
| Stem | Leaves |
|---|---|
| 1 | 2 4 4 8 |
| 2 | 1 5 |
Key: 1 | 2 means 12 marks. Repeated leaves represent repeated observations. Without a key, the same digits could denote decimals or other units. A back-to-back plot compares two groups with a common stem scale.
A grouped mean needs representative values
For classes 0 < t ≤ 10, 10 < t ≤ 20, 20 < t ≤ 30, 30 < t ≤ 40 with frequencies 4, 8, 6, 2, use midpoints 5, 15, 25, 35. The estimated total is 4(5) + 8(15) + 6(25) + 2(35) = 360, so estimated mean is 360/20 = 18 minutes.
It is an estimate because every observation was replaced by its class midpoint. The actual total may differ. Do not average the four midpoints without frequency weights unless all class frequencies are equal.
Check your understanding 1 Weight the representative values
Two equal-width classes have midpoints 10 and 20 and frequencies 3 and 7. Estimate the mean. Explain why 15 is not the correct estimate.
Show answer
The estimated total is 3(10) + 7(20) = 170 across 10 observations, giving 17. The midpoint average 15 weights the classes equally even though seven of the ten observations are in the second class.
Keep track of this lesson
Mark the lesson done when you have worked through it.
Lesson progress is optional and kept on this device.
Loading lesson controls…
Your lesson mark records your own study. Checks are kept separately in My Learning.