Letters, expressions and equations

Distinguish an expression from an equation and undo operations while keeping equality.

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A letter holds the place of a number

You can write a rule before you know the number in it. A notebook costs an unknown number of dollars. Let n be the cost of one notebook in dollars. Three identical notebooks cost 3 × n, usually written 3n. With a $2 delivery charge, the total cost is 3n + 2 dollars.

The letter stands for a number, not for the object “notebook”. You could choose c instead, provided you say what c means and use it consistently. Every n in this rule represents the same cost. The notation 3n means multiplication, not a two-digit number beginning with 3.

An expression, such as 3n + 2, gives a rule for a value. It has no equals sign telling you what that value must be.

Check your understanding 1 Choose and use a letter

A ribbon has an unknown length in centimetres. A second ribbon is 6 cm longer. Choose a letter for the first length, say what it represents, and write an expression for the second length.

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One choice is: let r be the first ribbon’s length in centimetres. The second length is r + 6 cm. You might use a different letter; its meaning and its use must agree. The expression 6r would describe six times the first length, which is a different relationship.

Read the operation and its order

A letter can take the place of a number in each of the four operations:

  • a + 3: add 3 to a.
  • a-3: subtract 3 from a.
  • 3a: multiply a by 3. You can also write a × 3.
  • a/3: divide a by 3. You can also write a÷3.

Addition and multiplication allow the two numbers to swap: a + 3 = 3 + a and 3a = a × 3. Subtraction and division need more care. “Subtract a from 3” is 3-a, not a-3. “Divide 3 by a” is 3/a, not a/3. For a = 6, those two divisions give 1/2 and 2 respectively.

Check your understanding 2 Move between words and symbols

Write an expression for each description, then describe the last expression in words:

  • subtract b from 9;
  • share b litres equally among 4 containers;
  • 7b.
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The expressions are 9-b and b/4 litres per container. The expression 7b means seven times b. It does not mean 7 + b. Testing b = 8 helps distinguish the sharing expressions: b/4 gives 2 litres per container, whereas 4/b gives 1/2.

Combine quantities of the same kind

4a + 3a = 7a: four lots plus three lots make seven lots. Therefore 4a + 3a + 5 = 7a + 5. The five is a number of ones, not another five lots of a. For a = 2, the original and simplified expressions both give 19.

The number multiplying a letter is its coefficient. An a on its own means 1a. Keep each addition or subtraction with its term. For 9b-2b + 4, nine lots minus two lots leave seven lots, so the result is 7b + 4.

Different letters need separate groups. For example,

3a + 2a + 4b-b = 5a + 3b.

You cannot combine this to 8a or 8b: the two letters may represent different numbers. Fractions of the same unknown can combine too: a/3 + 2a/3 = a. The three thirds make one whole a.

Check your understanding 3 Repair a simplification

A learner writes 6p-2p + 3q + 5 = 12p. Simplify the original expression and explain why the learner’s grouping does not work.

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6p-2p + 3q + 5 = 4p + 3q + 5. Only the two p terms can combine. Keep the q term and the constant separate, and subtract the two lots of p. As a check, with p = 2 and q = 1, the original and 4p + 3q + 5 both give 16; 12p gives 24.

Substitute a value for each letter

To evaluate an expression, replace each letter with its given number, then calculate. Multiply or divide before adding or subtracting.

For the notebook rule 3n + 2, if n = 4, the total is 3 × 4 + 2 = 14 dollars. It is not 3 × (4 + 2): the delivery charge is added once, after the three notebook costs.

For 2a + 3b, with a = 2 and b = 3, the value is 2 × 2 + 3 × 3 = 4 + 9 = 13. Give each letter its own stated value. For a/2 when a = 3, the value is 3/2 = 11/2; substitution need not give a whole number.

Check your understanding 4 Use both given values

Find the value of 5a-2b + 1 when a = 3 and b = 4. Write the substitution before calculating.

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5 × 3-2 × 4 + 1 = 15-8 + 1 = 8. The b term uses 4, not the value 3 given for a. The subtraction remains subtraction.

An equation makes a claim of equality

An equation says that two expressions are equal. Solving it means finding the number that makes the claim true. If the notebook total is $17, then 3n + 2 = 17.

Both sides can be pictured as equal loads on a balance. Removing the same load from each side preserves balance. Changing only one side would break equality. To isolate n:

  • Subtract 2 from both sides: 3n = 15.
  • Divide both sides by 3: n = 5.
  • Check in the original equation: 3 × 5 + 2 = 17.

For 4x-3 = 17, add 3 to both sides to undo subtraction: 4x = 20. Divide both sides by 4 to get x = 5. Check 4 × 5-3 = 17. An operation is undone by its inverse, not by repeating it.

Sometimes the letter appears on both sides. For 5n + 2 = 2n + 23, subtract 2n from both sides to get 3n + 2 = 23. Subtract 2 to get 3n = 21, then divide by 3: n = 7. Checking gives 37 on each side. You could instead subtract 2 first; each step must keep the two sides equal.

Whole-number coefficients do not force a whole-number answer. For 6x = 9, dividing both sides by 6 gives x = 9/6 = 11/2. Checking gives 6 × 11/2 = 9.

Check your understanding 5 Explain the inverse steps

A number is multiplied by 5 and then 7 is subtracted. The result is 28. Write an equation and solve it. Show how your steps keep equality, then check your answer in the original equation.

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5x-7 = 28. Add 7 to both sides: 5x = 35. Divide both sides by 5: x = 7. Check 5 × 7-7 = 28. Subtracting another 7 would not undo the original subtraction.

Change the unknown, keep the story

A taxi-fare model is 4 + 2d dollars for a journey of d km. Using this stated model, find the fare for 6 km, then the distance corresponding to a $20 fare. State the unit of each answer. This is a model for this task, not an actual company’s pricing.

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For 6 km: 4 + 2 × 6 = 16 dollars. For $20: 4 + 2d = 20, so 2d = 16 and d = 8 km. Check 4 + 2 × 8 = 20. In one task the distance is given and you evaluate an expression; in the other it is unknown and you solve an equation.

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