Letters, expressions and equations

Distinguish an expression from an equation and undo operations while keeping equality.

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Choose a letter for the unknown number

A letter stands for a number you do not know yet.

A notebook’s price is unknown. Let n mean the cost of one notebook in dollars. Every n card below names that same cost. The letter stands for a number, not for the object “notebook”.

The same cost repeats

The three notebook costs are equal. The delivery charge is a separate amount paid once.

Each n card is the same one-notebook cost. The delivery charge is added once.
Figure data

This table is included in print while it is open.

Values shown on the cards
SetValues
Three notebooksn dollars; n dollars; n dollars
One delivery2 dollars

Write an expression for the three notebooks alone, before delivery.

Connect the cards to the notationHide answer
n + n + n = 3 × n = 3n.

The 3 is a coefficient: it counts the three equal lots of n. Including the one delivery charge gives 3n + 2 dollars. The notation 3n does not mean a two-digit number beginning with 3.

Check your understanding 1

Choose and use a letter

A ribbon has an unknown length in centimetres. A second ribbon is 6 cm longer. Choose a letter for the first length, say what it represents, and write an expression for the second length.

Keep working notes
Your letter names the first ribbon’s length. How do you get the second?

Show answerHide answer

One choice is: let r be the first ribbon’s length in centimetres. The second length is r + 6 cm. A different letter works if its meaning and use agree. The expression 6r would describe six times the first length.

Read the operation and its order

A letter can take the place of a number in each operation:

  • a + 3: add 3 to a.
  • a-3: subtract 3 from a.
  • 3a: multiply a by 3.
  • a/3: divide a by 3.

Addition and multiplication let the two quantities swap: a + 3 = 3 + a and 3a = a × 3. For subtraction and division, which quantity comes first matters.

“Subtract a from 3” starts with 3, so it is 3-a. “Divide 3 by a” is 3/a, for a ≠ 0. If a = 6, then 3/a = 1/2 but a/3 = 2.

Check your understanding 2

Move between words and symbols

Write an expression for subtract b from 9.

Now write an expression for share b litres equally among 4 containers.

Finally, describe 7b by naming the two quantities and the operation.

Keep working notes
Which expression means subtract b from 9?

Show answerHide answer

The expressions are 9-b and b/4 litres per container. The expression 7b means seven times b, not 7 + b. For b = 8, sharing b litres among 4 containers gives 2 litres each. The reversed expression 4/b gives 1/2, so it describes a different division.

Read both quantities in a division

A fraction bar also means division. Read the numerator as the amount being divided and the denominator as the divisor. The expression 5/c requires c ≠ 0.

Check with a valueHide answer

If c = 10, then 5/c = 5/10 = 1/2. Reversing it gives 10/5 = 2. The same two quantities do not guarantee the same result.

Which terms count the same kind of amount?

Join terms of the same kind

Four lots of a and three lots of a make seven lots of a. The constant 5 counts ones, not more lots of a.

Group equal unknown values

Join the two groups of a cards. Keep the five ones as a different kind of term.

The a cards name equal unknown values. The constant is five ones, not five more a cards.
Figure data

This table is included in print while it is open.

Values shown on the cards
SetValues
First groupa; a; a; a
Second groupa; a; a
Constant5 ones

Different letters need separate groups. For example,

3a + 2a + 4b-b = 5a + 3b.

An a alone means 1a, and a -b means subtract one lot of b. Keep every addition or subtraction attached to its term. The two letters may have different values, so the expression cannot become 8a or 8b.

Check your understanding 3

Repair a simplification

A learner writes 6p-2p + 3q + 5 = 12p. Simplify the original expression and explain why the grouping does not work.

Keep working notes
Which terms may combine in 6p − 2p + 3q + 5?

Show answerHide answer
6p-2p + 3q + 5 = 4p + 3q + 5.

Only the two p terms combine. With p = 2 and q = 1, both the original and the collected expression give 16. The proposed 12p gives 24. Checking a value can expose a mistake; the like-term grouping explains why the correct expression works for every allowed value.

Fractions can count parts of the same unknown

Let a be a positive length. Each full strip below has length a. One third of a and two thirds of that same a make one whole a.

Keep the same unknown whole

Each full strip is one equal-sized whole.

Every full strip is the same length a. Combine one third and two thirds of that length.
Figure data

This table is included in print while it is open.

Equal parts in the picture
WholeParts in order
One third of amarked; empty; empty
Two thirds of amarked; marked; empty
Together: one whole amarked; marked; marked
Show workingHide answer
a/3 + 2a/3 = 3a/3 = a.

The picture uses a positive length to show the grouping. The same rule works when a is zero too.

Substitute a value for each letter

To evaluate an expression, replace each letter by its stated number, then calculate. For the notebook rule 3n + 2, let n = 4:

3n + 2 = 3 × 4 + 2; = 14 dollars.

Multiply before adding. The delivery charge is added once; 3 × (4 + 2) would charge it three times.

Check your understanding 4

Use both given values

Find 5a-2b + 1 when a = 3 and b = 4. Write the substitution before calculating.

Keep working notes
Which substitution uses a = 3 and b = 4 in 5a − 2b + 1?

Show answerHide answer
5a-2b + 1 = 5 × 3-2 × 4 + 1; = 15-8 + 1; = 8.

The b term uses 4, not the value 3 shown for a. The subtraction remains subtraction.

Substitution need not give a whole number. Find a/2 when a = 3.

Show workingHide answer
a/2 = 3/2 = 1 1/2.

What must you do to both sides to keep them equal?

Keep both sides equal

An expression, such as 3n + 2, gives a rule for a value. An equation, such as 3n + 2 = 17, says that two values are equal. Solving finds the number that makes that equality true.

Change both sides together

The two cards in each row name equal values. Subtracting two from both sides, then dividing both sides by three, preserves equality.

Each row keeps the left and right values equal. Card sizes do not represent their amounts.
Figure data

This table is included in print while it is open.

Values shown on the cards
SetValues
Start: equal values3n + 2; 17
Subtract 2 from both3n; 15
Divide both by 3n; 5
3n + 2 = 17; 3n = 15; n = 5.

Removing the same amount from both sides keeps equality, like removing equal loads from a balance. Dividing both sides into three equal groups also keeps equality. Check: 3 × 5 + 2 = 17.

Check your understanding 5

Explain the inverse steps

A number is multiplied by 5 and then 7 is subtracted. The result is 28. Write an equation and solve it. Show how your steps keep equality, then check in the original equation.

Keep working notes
Which inverse steps solve 5x − 7 = 28?

Show answerHide answer
5x-7 = 28; 5x = 35; x = 7.

Add 7 to both sides, then divide both sides by 5. Check 5 × 7-7 = 28. Subtracting another 7 would not undo the original subtraction.

Gather the unknown when it appears on both sides

For 5n + 2 = 2n + 23, remove the same 2n from each side:

5n + 2 = 2n + 23; 3n + 2 = 23; 3n = 21; n = 7.

Then remove 2 from both sides and divide both by 3. Substitution gives 37 on each side. You could subtract 2 before subtracting 2n; the steps need to preserve equality, not follow one fixed order.

Try a new equation: 6p + 1 = 2p + 17.

Show workingHide answer
6p + 1 = 2p + 17; 4p + 1 = 17; 4p = 16; p = 4.

Subtract 2p, subtract 1, then divide by 4 on both sides. Check: 6 × 4 + 1 = 25 and 2 × 4 + 17 = 25.

Find an answer that is a fraction

For 6x = 9, divide both sides by 6:

x = 9/6 = 3/2 = 1 1/2.

The coefficient 6 is a whole number, but the solution need not be whole. Check: 6 × 1 1/2 = 9.

Now solve 8u = 10. Give the exact value of u.

Show workingHide answer
u = 10/8 = 5/4 = 1 1/4.

Change the unknown, keep the story

A taxi-fare model is 4 + 2d dollars for a journey of d km. Using this stated model, find the fare for 6 km, then the distance for a 20-dollar fare. This is a model for this task, not an actual company’s pricing.

Keep working notes
For a known fare of 20 dollars, which equation finds the distance?

Show answerHide answer

For the known distance, evaluate:

4 + 2 × 6 = 16 dollars.

For the known fare, solve:

4 + 2d = 20; 2d = 16; d = 8 km.

Check 4 + 2 × 8 = 20. The relationship stays the same; the question changes which quantity is unknown.

For a grown-up

Pip’s synthetic voice uses the University of Edinburgh’s Alba speech dataset, via Piper’s Alba voice, under CC BY 4.0. Audio is optional.

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