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You can summarise a frequency table once you know how often each value occurs. Here, recover those frequencies from running totals or two groups. For the basic meanings, revisit mean, median and mode.
A running total already includes earlier values
A frequency tells you how many at this value. A cumulative count tells you how many up to this value.
| Value | Cumulative count | New observations at this value |
|---|---|---|
| 1 | 2 | 2 |
| 4 | 5 | 5 − 2 = 3 |
The five observations are 1, 1, 4, 4, 4. The second running total includes the first two observations. It does not mean that five separate observations equal 4.
Data table
| Category | Value 1 | Value 4 |
|---|---|---|
| Up to 1 | 2 | 0 |
| Up to 4 | 2 | 3 |
Recover each new count by subtracting the previous running total. At the first listed value, subtract zero.
Worked example 1
Recover frequencies, then find the median
Worked example 1
Recover frequencies, then find the median
The table shows running totals for the number of pets owned by 12 pupils.
| Pets | Cumulative count |
|---|---|
| 1 | 3 |
| 2 | 7 |
| 3 | 8 |
| 4 | 12 |
Find the median number of pets.
Show full solutionHide solution
Recover each frequency
Method
Subtract the previous running total from each one.Reason
Each running total already includes all the smaller values, so only the increase belongs to the new value.Working
Answer
Pets Frequency 1 3 − 0 = 3 2 7 − 3 = 4 3 8 − 7 = 1 4 12 − 8 = 4 The frequencies add to 12, the last running total.
Locate the middle positions
Method
With 12 observations, the median is halfway between the 6th and 7th.Reason
For an even count there is no single middle observation, so the two central positions are used.Working
Answer
Positions 1–3 have 1 pet and positions 4–7 have 2 pets. So the 6th and 7th observations are both 2.
State the median
Working
Answer
Median = (2 + 2)/2 = 2 pets.
Quick check
The running totals tell you directly that 7 pupils own 2 pets or fewer, so the 6th and 7th pupils, in order, own 2. Taking the middle of the listed values 1, 2, 3, 4 gives 2.5; that ignores how many pupils have each value.
Guided practice 1
Recover a missing separate frequency
Guided practice 1
Recover a missing separate frequency
Values 0, 2 and 5 have cumulative counts 2, 7 and 10. Find the separate frequency at 2 and the mean of all ten observations. First subtract consecutive totals, then form a weighted total.
Try this before viewing the solution
Hint 1
Separate totals from frequencies
Does the cumulative count at 2 include observations of value 0?
Hint 2
Recover then weight the counts
Subtract consecutive cumulative counts for the separate frequencies. Multiply each value by its frequency and divide their sum by the total count.
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Recover the separate frequencies
Method
Subtract the previous cumulative count from each new total.Reason
Each cumulative count includes all earlier values, so the increase isolates the newly included value.Working
Answer
At 0: 2. At 2: 7-2 = 5. At 5: 10-7 = 3.
Find the total of the observations
Method
Weight each value by its recovered frequency.Reason
Repeated observations must contribute once per occurrence, even though the table lists each distinct value only once.Working
Answer
Total = 0(2) + 2(5) + 5(3) = 25.
Divide by the observation count
Method
Use all ten observations in the denominator.Reason
The mean is the total shared equally across observations, not across the three distinct values.Working
Answer
The frequency at 2 is 5 and the mean is 25/10 = 2.5.
Quick check
2 + 5 + 3 = 10 matches the last running total; the mean lies between 0 and 5.
Find the largest increase
Check your understanding 1
Find every modal value
Check your understanding 1
Find every modal value
The table records how many books were borrowed per visit. Only the listed values are possible. Find every mode of the observations. Separate multiple values with commas.
| Value | Cumulative count |
|---|---|
| 0 | 1 |
| 2 | 4 |
| 5 | 7 |
| 9 | 7 |
Show answerHide answer
| Books per visit | Separate frequency |
|---|---|
| 0 | 1 − 0 = 1 |
| 2 | 4 − 1 = 3 |
| 5 | 7 − 4 = 3 |
| 9 | 7 − 7 = 0 |
The complete mode set is 2 and 5. The running total 7 is neither a book value nor an individual frequency. No visit borrowed 9 books.
As a check, the recovered frequencies add to 7, the final cumulative count.
A flat count adds no observations
Check your understanding 2
Locate the observed extremes
Check your understanding 2
Locate the observed extremes
Range is largest observed value minus smallest observed value. First decide which listed values actually contribute observations.
This table records temperature changes in °C. Find the range of the observed changes.
| Value | Cumulative count |
|---|---|
| −6 | 0 |
| −2 | 2 |
| 1 | 5 |
| 4 | 6 |
| 9 | 6 |
Locate the observed extremesHide answer
The separate frequencies are 0, 2, 3, 1, 0. No observations equal −6°C or 9°C. The observed values are −2°C, 1°C and 4°C.
Using the first and last labels would give 15°C, but both of those labelled values have zero observations. A running-count table can list a value without any observation at that value.
Take out the same-valued observations
When one group is removed, reconstruct the population you were asked to summarise.
| Value | Whole group | Removed group | Remaining group |
|---|---|---|---|
| 2 | 6 | 4 | 6 − 4 = 2 |
| 5 | 3 | 1 | 3 − 1 = 2 |
The remaining group is 2, 2, 5, 5. Subtract counts within each row: removing four observations equal to 2 cannot remove an observation equal to 5.
The remaining count also agrees with the group totals: (6 + 3)-(4 + 1) = 4.
Summarise the group that remains
Check your understanding 3
Choose the remaining population
Check your understanding 3
Choose the remaining population
The table records the number of books carried in each bag. Some bags are taken away. Find every mode for the bags that remain. Separate multiple values with commas.
| Value | Whole group | Removed group |
|---|---|---|
1 | 5 | 4 |
3 | 4 | 1 |
6 | 6 | 3 |
9 | 2 | 2 |
Show answerHide answer
| Books in a bag | Whole-group frequency | Remaining frequency |
|---|---|---|
| 1 | 5 | 5 − 4 = 1 |
| 3 | 4 | 4 − 1 = 3 |
| 6 | 6 | 6 − 3 = 3 |
| 9 | 2 | 2 − 2 = 0 |
The whole group has only one mode, 6 books. The remaining group has two modes: 3 and 6 books. Using the largest whole-group count would miss the changed population.
Recover the count before the middle
Check your understanding 4
Locate the remaining middle pair
Check your understanding 4
Locate the remaining middle pair
This table records temperature changes in °C. Readings from a separate experiment are removed. Find the median change for the readings that remain.
| Value | Whole group | Removed group |
|---|---|---|
0 | 2 | 1 |
2 | 5 | 3 |
6 | 4 | 1 |
Order the remaining observationsHide answer
The remaining frequencies are 1, 2 and 3, giving six observations:
0, 2, 2, 6, 6, 6 °C.
The two central positions are different observations, even when a table compresses several equal observations into one row. The median need not itself occur in the data.
Use the recovered data for a different summary
Check your understanding 5
Choose a count and weighted total
Check your understanding 5
Choose a count and weighted total
The table records changes in water level, in centimetres. Find their mean. Choose the count and total you need before entering it.
| Value | Cumulative count |
|---|---|
| −1 | 1 |
| 0 | 3 |
| 3 | 5 |
Show answerHide answer
The frequencies are 1, 2 and 2, so the five observations are −1, 0, 0, 3 and 3 cm.
Dividing by the three rows would count different values rather than observations. Adding the running totals would count some observations more than once.
Check which information the table retains
These tables list every possible individual value. Their cumulative differences or group differences recover exact frequencies, so the summaries above are exact.
A table of class intervals is different: it does not retain individual values within each class. Midpoints or interpolation can give estimates, but cannot recover the exact original observations.
Try it yourself 1
Remove a group before finding its median
Try it yourself 1
Remove a group before finding its median
Values 1, 3 and 7 occur 3, 4 and 3 times in a whole group. A subgroup containing two 1s, one 3 and one 7 is removed. Find the median of the remaining observations. Show how you recover the remaining population.
Write your answer, then compare it with the solution
Show solution step by stepHide solution
Subtract the subgroup frequencies
Method
Remove each stated subgroup count from its matching value’s frequency.Reason
Removing four observations changes both the total count and the relative frequency of each value.Working
Answer
Remaining counts: at 1, 3-2 = 1; at 3, 4-1 = 3; at 7, 3-1 = 2.
Rebuild the ordered remaining data
Method
Write each value the number of times it remains.Reason
The median depends on ordered positions, so the six remaining observations must be located after removal.Working
Answer
The remaining list is 1, 3, 3, 3, 7, 7.
Locate the new middle pair
Method
Average the third and fourth values.Reason
An even count has two central positions; neither the old group nor the removed subgroup determines this median.Working
Answer
Both central values are 3, so the remaining median is (3 + 3)/2 = 3.
Quick check
The count is 10-4 = 6, agreeing with 1 + 3 + 2. Compare row subtraction, middle positions and the resulting median.
Common mistakes
- Reading a cumulative count as a frequency. Subtract the previous running total to find how many are at each value.
- Counting a value whose running total did not change. A flat cumulative count means no observations at that value.
- Summarising the wrong group. After removing a group, recalculate from the remaining frequencies.
- Giving only one mode. List every value with the greatest frequency.
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Syllabus and review details
- G1 Mathematics 2027 · 2027
- G2 Mathematics 2027 · 2027
- G3 Mathematics 2027 · 2027
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